专注于 JetBrains IDEA 全家桶,永久激活,教程
持续更新 PyCharm,IDEA,WebStorm,PhpStorm,DataGrip,RubyMine,CLion,AppCode 永久激活教程

高大上技术之sql解析

Question: 为何sql解析和高大上有关系?
Answer:因为数据库永远都是系统的核心,CRUD如此深入码农的内心。。。如果能把CRUD改造成高大上技术,如此不是造福嘛。。。

CRUD就是Create, Read, Update, Delete,转换成sql语句就是insert, select, update, delete

普通场景下,insert也就是一个insert了,没什么高深。。。
高并发场景下,insert就不是一个insert了,而是千千万万个insert。。。可以用到的技术有排队、分表、分区、分仓、缓存同步

普通场景下,select也就是一个select了,没什么高深。。。
高并发场景下,select就不是一个select了,而是千千万万,再千千万万个select。。。可以用到的技术有缓存、普通读写分离、深入读写分离、不锁、past锁、还有分表、分区、分仓。。。

你说这么多东西,是全部在一个sql中全部自动化掉好呢,还是让我们码农一个一个考虑,再一个一个写成代码逻辑的好?

肯定两种声音都有,还肯定有第三种声音。。。所以我还是照着我自己的思路来说吧,你们随便发挥想象。。。

我要让一个sql全部解决上面的效果,或者接近上面的效果

如何解决,那就是,以SELECT语句为例

1、 解析SELECT语句
2、 解析牵涉到的表、字段、主键
3、 解析是否用到了自己扩展的dsl函数
4、 找到相应表的分区函数
5、 找到相应表的缓存配置
6、 找到dsl函数对应的真实函数
7、 其他

比如有2个SELECT语句:

1、 SELECT UserID, UserName, Age FROM Users WHERE UserID=’某个guid’
2、 SELECT COUNT(1) FROM Users

很简单的两句sql,可是Users是个虚拟表,真实表有16个表:Users.[A-F], Users.[0-9],分表策略为根据主键ID的第一个字母来分表, 因此:

  • 第一句sql需要先解析where条件中UserID=’guid’这个UserID是否为pkid,以及这个’guid’的值,然后根据guid的值调用分表策略函数得到相应的分表后缀,然后用类似下面这个sql来真实查询:SELECT UserID, UserName, Age FROM [Users.A] WHERE UserID=’axxxxx-xxxxx-xxxx-xx’
  • 第二句sql其实是最终变成了16条sql来得到各个分表的count值,然后在程序中累加这些分表的count值

其他:

  • 其他类似缓存、队列、自定义的扩展函数,都类似于上可以得到解决。

由于只是个demo,所以没有实现上述全部功能,我们只说下关键原理、和代码。。。

我们用antlr来做词法解析、语法解析,然后再用tree walker把antlr解析出来的东西转换为我们要的数据结构,比如:SelectTerms, TableName, WhereClause, OrderByClause等

奥,我们还得写一个规则文件让Antlr吃进去,然后antlr就能调用tree walker生成我们要的数据结构了

(大家赶紧补下编译原理之类的基础知识以及ANTLR知识)

grammar SelectSQL;

compileUnit
    :    start
    ;

WS
    :    [ \t\n\r]+ -> skip
    ;

COMMA:',';
SELECT: 'SELECT';
STAR:'*';
FROM:'FROM';
WHERE:'WHERE';
ORDERBY:'ORDER BY';
DIRECTION:'ASC'|'DESC';
CHAR: 'a'..'z'|'A'..'Z';
NUM: '0'..'9';
STRING:'\'' .*? '\'';
LB:'(';
RB:')';
LBRACE:'[';
RBRACE:']';
CONDITIONS_OPERATOR    
    :'AND'
    |'OR'
    ;
CONDITION_OPERATOR    
    :'='
    |'>'
    |'<'
    |'<>'
    |'!='
    |'>='
    |'<='
    ;
FCOUNT:'COUNT';

start
    :statement_list
    ;

statement_list
    :statement statement*
    ;

statement
    :selectStatement
    ;

selectStatement
    :selectStmt fromStmt whereStmt? orderbyStmt?
    ;

selectStmt
    :SELECT columns
    ;

columns
    :column (COMMA column)*
    ;

column
    : identifier
    | LBRACE identifier RBRACE
    | functionStmt
    | STAR
    ;

functionStmt
    :function LB (parameters) RB
    ;

function
    :FCOUNT
    ;

parameters
    : parameter (COMMA parameter)*
    ;

parameter
    : identifier
    | integer
    | string
    | STAR
    ;

fromStmt
    :FROM table
    ;

table
    : identifier
    | LBRACE identifier RBRACE
    ;

whereStmt
    : WHERE conditions
    ;

conditions
    : condition (CONDITIONS_OPERATOR condition)* 
    ;

condition
    :left CONDITION_OPERATOR right
    ;

left
    : parameter
    ;

right
    : parameter
    ;

orderbyStmt
    :ORDERBY sortStmt
    ;

sortStmt
    : sortCondition (COMMA sortCondition)*
    ;

sortCondition
    :sortColumn DIRECTION
    ;

sortColumn
    : identifier
    | LBRACE identifier RBRACE
    ;

identifier
    :CHAR (CHAR|NUM)*
    ;
integer
    :NUM+
    ;
string
    : STRING
    ;

真心呼唤广大开发人员深入编译原理之类的基础技术!

在eclipse中输入解析sql文本后,会被解析成tree

72_1.png

开源世界真强大啊,有yacc, flex, bison, antlr这些现成的解析工具。

我们先在eclipse中把规则测试通过后,再把这个.g4规则文件拷贝到我们的visual studio中,如下:

72_2.png

然后只要这个g4文件一保存,antlr的vs插件就会自动根据规则文件生成相关名称的词法解析类、文法解析类、以及我们即将要改写的TreeListener

72_3.png

SelectSQLBaseListener:就是antlr插件自动生成的抽象类,我们的改动都是基于这个类,来做override改写(针对规则的enter/exit)

EnterXXXXX/ExitXXXX: 对应规则文件中的规则名称,Enter/Exit代表进入规则以及离开规则之前的行为动作

demo控制台程序运行输出效果:

输入SQL:

                    SELECT * FROM users
                    SELECT userId, userName FROM users
                    SELECT COUNT(1) FROM users
                    SELECT COUNT(*) FROM users
                    SELECT userId, userName FROM users ORDER BY userName DESC
                    SELECT userId, userName FROM users WHERE userId='1212121' ORDER BY userName DESC

输出SQL:
          select * from [users.0]
          select * from [users.1]
          select * from [users.2]
          select * from [users.3]
          select * from [users.4]
          select * from [users.5]
          select * from [users.6]
          select * from [users.7]
          select * from [users.8]
          select * from [users.9]
          select * from [users.a]
          select * from [users.b]
          select * from [users.c]
          select * from [users.d]
          select * from [users.e]
          select * from [users.f]
          select userId, userName from [users.0]
          select userId, userName from [users.1]
          select userId, userName from [users.2]
          select userId, userName from [users.3]
          select userId, userName from [users.4]
          select userId, userName from [users.5]
          select userId, userName from [users.6]
          select userId, userName from [users.7]
          select userId, userName from [users.8]
          select userId, userName from [users.9]
          select userId, userName from [users.a]
          select userId, userName from [users.b]
          select userId, userName from [users.c]
          select userId, userName from [users.d]
          select userId, userName from [users.e]
          select userId, userName from [users.f]
          select COUNT(1) from [users.0]
          select COUNT(1) from [users.1]
          select COUNT(1) from [users.2]
          select COUNT(1) from [users.3]
          select COUNT(1) from [users.4]
          select COUNT(1) from [users.5]
          select COUNT(1) from [users.6]
          select COUNT(1) from [users.7]
          select COUNT(1) from [users.8]
          select COUNT(1) from [users.9]
          select COUNT(1) from [users.a]
          select COUNT(1) from [users.b]
          select COUNT(1) from [users.c]
          select COUNT(1) from [users.d]
          select COUNT(1) from [users.e]
          select COUNT(1) from [users.f]
          select COUNT(*) from [users.0]
          select COUNT(*) from [users.1]
          select COUNT(*) from [users.2]
          select COUNT(*) from [users.3]
          select COUNT(*) from [users.4]
          select COUNT(*) from [users.5]
          select COUNT(*) from [users.6]
          select COUNT(*) from [users.7]
          select COUNT(*) from [users.8]
          select COUNT(*) from [users.9]
          select COUNT(*) from [users.a]
          select COUNT(*) from [users.b]
          select COUNT(*) from [users.c]
          select COUNT(*) from [users.d]
          select COUNT(*) from [users.e]
          select COUNT(*) from [users.f]
          select userId, userName from [users.0]  order by userName DESC
          select userId, userName from [users.1]  order by userName DESC
          select userId, userName from [users.2]  order by userName DESC
          select userId, userName from [users.3]  order by userName DESC
          select userId, userName from [users.4]  order by userName DESC
          select userId, userName from [users.5]  order by userName DESC
          select userId, userName from [users.6]  order by userName DESC
          select userId, userName from [users.7]  order by userName DESC
          select userId, userName from [users.8]  order by userName DESC
          select userId, userName from [users.9]  order by userName DESC
          select userId, userName from [users.a]  order by userName DESC
          select userId, userName from [users.b]  order by userName DESC
          select userId, userName from [users.c]  order by userName DESC
          select userId, userName from [users.d]  order by userName DESC
          select userId, userName from [users.e]  order by userName DESC
          select userId, userName from [users.f]  order by userName DESC
          select userId, userName from [users.0] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.1] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.2] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.3] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.4] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.5] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.6] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.7] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.8] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.9] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.a] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.b] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.c] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.d] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.e] WHERE userId='1212121' order by userName DESC
          select userId, userName from [users.f] WHERE userId='1212121' order by userName DESC

希望大家能对基础技术真正感兴趣,赶紧学习编译原理、antlr吧。

很抱歉没能提供详细原理说明,大家baidubaidu就都有了。

代码下载 http://files.cnblogs.com/files/aarond/SQLParser_Select.rar

文章永久链接:https://tech.souyunku.com/38922

未经允许不得转载:搜云库技术团队 » 高大上技术之sql解析

JetBrains 全家桶,激活、破解、教程

提供 JetBrains 全家桶激活码、注册码、破解补丁下载及详细激活教程,支持 IntelliJ IDEA、PyCharm、WebStorm 等工具的永久激活。无论是破解教程,还是最新激活码,均可免费获得,帮助开发者解决常见激活问题,确保轻松破解并快速使用 JetBrains 软件。获取免费的破解补丁和激活码,快速解决激活难题,全面覆盖 2024/2025 版本!

联系我们联系我们